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5-3x^2=-31
We move all terms to the left:
5-3x^2-(-31)=0
We add all the numbers together, and all the variables
-3x^2+36=0
a = -3; b = 0; c = +36;
Δ = b2-4ac
Δ = 02-4·(-3)·36
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*-3}=\frac{0-12\sqrt{3}}{-6} =-\frac{12\sqrt{3}}{-6} =-\frac{2\sqrt{3}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*-3}=\frac{0+12\sqrt{3}}{-6} =\frac{12\sqrt{3}}{-6} =\frac{2\sqrt{3}}{-1} $
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